(-3-2x)^2-4x^2-3x-17=-3+11x

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Solution for (-3-2x)^2-4x^2-3x-17=-3+11x equation: 



(-3-2x)^2-4x^2-3x-17=-3+11x

We move all terms to the left:

(-3-2x)^2-4x^2-3x-17-(-3+11x)=0

We add all the numbers together, and all the variables

-4x^2+(-2x-3)^2-3x-(11x-3)-17=0

We add all the numbers together, and all the variables

-4x^2-3x+(-2x-3)^2-(11x-3)-17=0

We get rid of parentheses

-4x^2-3x+(-2x-3)^2-11x+3-17=0

We add all the numbers together, and all the variables

-4x^2-14x+(-2x-3)^2-14=0

We move all terms containing x to the left, all other terms to the right

-4x^2-14x+(-2x-3)^2=14

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